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THE SCENARIO: We have 14 observations on INCOME (the income of a college student) and EXPEND (the consumption expenditures of each student). Suppose we are interested in knowing, on average, the approximate relationship beween EXPEND and the INCOME that makes it possible. Thus EXPEND is the dependent (Y) variable and INCOME is the explanatory (X) variable. First, we will want to be able to express E[Y] as a linear function of X. This requires using OLS to find the parameters b1 and b2 such that E[Y] = b1 + b2(X). Or, we could refer to E[EXPEND] = b1 + b2 (INCOME).
Once the model is estimated, we might be interested in some hypotheses.
|_sample 1 14
|_read(mpc.dat) income expend
UNIT 88 IS NOW ASSIGNED TO: mpc.dat
2 VARIABLES AND 14 OBSERVATIONS STARTING AT OBS 1
|_stat / pcor
NAME N MEAN ST. DEV VARIANCE MINIMUM MAXIMUM
INCOME 14 155.00 41.278 1703.8 100.00 220.00
EXPEND 14 125.57 35.224 1240.7 80.000 180.00
CORRELATION MATRIX OF VARIABLES - 14 OBSERVATIONS
INCOME 1.0000
EXPEND 0.84385 1.0000
INCOME EXPEND
|_ols expend income
REQUIRED MEMORY IS PAR= 1 CURRENT PAR= 500
OLS ESTIMATION
14 OBSERVATIONS DEPENDENT VARIABLE = EXPEND
...NOTE..SAMPLE RANGE SET TO: 1, 14
R-SQUARE = 0.7121 R-SQUARE ADJUSTED = 0.6881
VARIANCE OF THE ESTIMATE-SIGMA**2 = 387.00
STANDARD ERROR OF THE ESTIMATE-SIGMA = 19.672
SUM OF SQUARED ERRORS-SSE= 4644.0
MEAN OF DEPENDENT VARIABLE = 125.57
LOG OF THE LIKELIHOOD FUNCTION = -60.4950
ANALYSIS OF VARIANCE - FROM MEAN
SS DF MS F
REGRESSION 11485. 1. 11485. 29.678
ERROR 4644.0 12. 387.00 P-VALUE
TOTAL 16129. 13. 1240.7 0.000
ANALYSIS OF VARIANCE - FROM ZERO
SS DF MS F
REGRESSION 0.23224E+06 2. 0.11612E+06 300.052
ERROR 4644.0 12. 387.00 P-VALUE
TOTAL 0.23688E+06 14. 16920. 0.000
VARIABLE ESTIMATED STANDARD T-RATIO PARTIAL STANDARDIZED ELASTICITY
NAME COEFFICIENT ERROR 12 DF P-VALUE CORR. COEFFICIENT AT MEANS
INCOME 0.72009 0.1322 5.448 0.000 0.844 0.8438 0.8888
CONSTANT 13.957 21.15 0.6599 0.522 0.187 0.0000 0.1112
|_test income=0
TEST VALUE = 0.72009 STD. ERROR OF TEST VALUE 0.13218
T STATISTIC = 5.4477715 WITH 12 D.F. P-VALUE= 0.00015
F STATISTIC = 29.678214 WITH 1 AND 12 D.F. P-VALUE= 0.00015
WALD CHI-SQUARE STATISTIC = 29.678214 WITH 1 D.F. P-VALUE= 0.00000
UPPER BOUND ON P-VALUE BY CHEBYCHEV INEQUALITY = 0.03369
|_test income=1
TEST VALUE = -0.27991 STD. ERROR OF TEST VALUE 0.13218
T STATISTIC = -2.1176290 WITH 12 D.F. P-VALUE= 0.05577
F STATISTIC = 4.4843528 WITH 1 AND 12 D.F. P-VALUE= 0.05577
WALD CHI-SQUARE STATISTIC = 4.4843528 WITH 1 D.F. P-VALUE= 0.03421
UPPER BOUND ON P-VALUE BY CHEBYCHEV INEQUALITY = 0.22300
|_stop
THE FINDINGS: Above, we identified three interesting hypotheses that might be tested using these data. What have we determined by our regression analysis?
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